[Jason]

Ridiculous claim!

Probability of an arbitrarily selected song being from the second half is assumed to be .5 (as in, a fair media player). Now, the probability of having eleven randomly selected songs from the first half is thus (.5)^11 (obviously). Now the probability of getting just ten songs all be from the first half is (.5)^10 (obviously). Now pay careful attention to the next step:

The probability, GIVEN THAT TEN SONGS HAVE BEEN FROM THE FIRST HALF, of having ELEVEN SONGS FROM THE FIRST HALF, is the probability of having eleven songs from the first half divided by the probability of having ten songs from the first half (conditional probability).

(.5)^11 / (.5)^10 = .5

So the probability is still 50-50!

Good luck. =)